python代码实现约瑟夫环列表示例及详细解释

以下是实现约瑟夫环问题的Python代码列表:

使用循环列表:

def josephus(n, k):
    circle = [i for i in range(1, n+1)]
    idx = 0
    while len(circle) > 1:
        idx = (idx + k - 1) % len(circle)
        circle.pop(idx)
    return circle[0]

使用循环链表:

class Node:
    def __init__(self, val):
        self.val = val
        self.next = None

def josephus(n, k):
    head = Node(1)
    curr = head
    for i in range(2, n+1):
        curr.next = Node(i)
        curr = curr.next
    curr.next = head  # make it a circular list

    prev = curr
    curr = head
    while prev.next != curr:
        for i in range(k-1):
            prev = curr
            curr = curr.next
        prev.next = curr.next
        curr = prev.next
    return curr.val

使用递归:

def josephus(n, k):
    if n == 1:
        return 1
    else:
        return (josephus(n-1, k) + k-1) % n + 1

其中,n代表总人数,k代表报数的步长。函数返回最后留下的人的编号。

 
  • 约瑟夫
匿名

发表评论

匿名网友
:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:
确定